RGB to binary in android

RGB to binary in android

I would like to find an android code that will assist me convert an RGB
image to a binary image. Please assist. Also kindly assist me to find out
how I can modify a code as this below to integrate it for an Adroid mobile
application.
package ij.process;
import java.awt.*;
/** This class processes binary images. */
public class BinaryProcessor extends ByteProcessor {
private ByteProcessor parent;
/** Creates a BinaryProcessor from a ByteProcessor. The ByteProcessor
must contain a binary image (pixels values are either 0 or 255).
Backgound is assumed to be white. */
public BinaryProcessor(ByteProcessor ip) {
super(ip.getWidth(), ip.getHeight(), (byte[])ip.getPixels(),
ip.getColorModel());
setRoi(ip.getRoi());
parent = ip;
}
static final int OUTLINE=0;
void process(int type, int count) {
int p1, p2, p3, p4, p5, p6, p7, p8, p9;
int inc = roiHeight/25;
if (inc<1) inc = 1;
int bgColor = 255;
if (parent.isInvertedLut())
bgColor = 0;
byte[] pixels2 = (byte[])parent.getPixelsCopy();
int offset, v=0, sum;
int rowOffset = width;
for (int y=yMin; y<=yMax; y++) {
offset = xMin + y * width;
p2 = pixels2[offset-rowOffset-1]&0xff;
p3 = pixels2[offset-rowOffset]&0xff;
p5 = pixels2[offset-1]&0xff;
p6 = pixels2[offset]&0xff;
p8 = pixels2[offset+rowOffset-1]&0xff;
p9 = pixels2[offset+rowOffset]&0xff;
for (int x=xMin; x<=xMax; x++) {
p1 = p2; p2 = p3;
p3 = pixels2[offset-rowOffset+1]&0xff;
p4 = p5; p5 = p6;
p6 = pixels2[offset+1]&0xff;
p7 = p8; p8 = p9;
p9 = pixels2[offset+rowOffset+1]&0xff;
switch (type) {
case OUTLINE:
v = p5;
if (v!=bgColor) {
if (!(p1==bgColor || p2==bgColor ||
p3==bgColor || p4==bgColor
|| p6==bgColor || p7==bgColor ||
p8==bgColor || p9==bgColor))
v = bgColor;
}
break;
}
pixels[offset++] = (byte)v;
}
if (y%inc==0)
parent.showProgress((double)(y-roiY)/roiHeight);
}
parent.hideProgress();
}
// 2012/09/16: 3,0 1->0
// 2012/09/16: 24,0 2->0
private static int[] table =
//0,1,2,3,4,5,6,7,8,9,0,1,2,3,4,5,6,7,8,9,0,1,2,3,4,5,6,7,8,9,0,1
{0,0,0,0,0,0,1,3,0,0,3,1,1,0,1,3,0,0,0,0,0,0,0,0,0,0,2,0,3,0,3,3,
0,0,0,0,0,0,0,0,3,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,2,0,0,0,3,0,2,2,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
2,0,0,0,0,0,0,0,2,0,0,0,2,0,0,0,3,0,0,0,0,0,0,0,3,0,0,0,3,0,2,0,
0,0,3,1,0,0,1,3,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,
3,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,2,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
2,3,1,3,0,0,1,3,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
2,3,0,1,0,0,0,1,0,0,0,0,0,0,0,0,3,3,0,1,0,0,0,0,2,2,0,0,2,0,0,0};
private static int[] table2 =
//0,1,2,3,4,5,6,7,8,9,0,1,2,3,4,5,6,7,8,9,0,1,2,3,4,5,6,7,8,9,0,1
{0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,2,0,2,2,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,2,0,2,0,0,0,0,0,0,0,0,0,2,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,2,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,2,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0};
/** Uses a lookup table to repeatably removes pixels from the
edges of objects in a binary image, reducing them to single
pixel wide skeletons. There is an entry in the table for each
of the 256 possible 3x3 neighborhood configurations. An entry
of '1' means delete pixel on first pass, '2' means delete pixel on
second pass, and '3' means delete on either pass. Pixels are
removed from the right and bottom edges of objects on the first
pass and from the left and top edges on the second pass. A
graphical representation of the 256 neighborhoods indexed by
the table is available at
"http://imagej.nih.gov/ij/images/skeletonize-table.gif".
*/
public void skeletonize() {
int pass = 0;
int pixelsRemoved;
resetRoi();
setColor(Color.white);
moveTo(0,0); lineTo(0,height-1);
moveTo(0,0); lineTo(width-1,0);
moveTo(width-1,0); lineTo(width-1,height-1);
moveTo(0,height-1); lineTo(width/*-1*/,height-1);
ij.ImageStack movie=null;
boolean debug = ij.IJ.debugMode;
if (debug) movie = new ij.ImageStack(width, height);
if (debug) movie.addSlice("-", duplicate());
do {
snapshot();
pixelsRemoved = thin(pass++, table);
if (debug) movie.addSlice(""+(pass-1), duplicate());
snapshot();
pixelsRemoved += thin(pass++, table);
if (debug) movie.addSlice(""+(pass-1), duplicate());
} while (pixelsRemoved>0);
do { // use a second table to remove "stuck" pixels
snapshot();
pixelsRemoved = thin(pass++, table2);
if (debug) movie.addSlice("2-"+(pass-1), duplicate());
snapshot();
pixelsRemoved += thin(pass++, table2);
if (debug) movie.addSlice("2-"+(pass-1), duplicate());
} while (pixelsRemoved>0);
if (debug) new ij.ImagePlus("Skel Movie", movie).show();
}
int thin(int pass, int[] table) {
int p1, p2, p3, p4, p5, p6, p7, p8, p9;
int bgColor = -1; //255
if (parent.isInvertedLut())
bgColor = 0;
byte[] pixels2 = (byte[])getPixelsCopy();
int v, index, code;
int offset, rowOffset = width;
int pixelsRemoved = 0;
int count = 100;
for (int y=yMin; y<=yMax; y++) {
offset = xMin + y * width;
for (int x=xMin; x<=xMax; x++) {
p5 = pixels2[offset];
v = p5;
if (v!=bgColor) {
p1 = pixels2[offset-rowOffset-1];
p2 = pixels2[offset-rowOffset];
p3 = pixels2[offset-rowOffset+1];
p4 = pixels2[offset-1];
p6 = pixels2[offset+1];
p7 = pixels2[offset+rowOffset-1];
p8 = pixels2[offset+rowOffset];
p9 = pixels2[offset+rowOffset+1];
index = 0;
if (p1!=bgColor) index |= 1;
if (p2!=bgColor) index |= 2;
if (p3!=bgColor) index |= 4;
if (p6!=bgColor) index |= 8;
if (p9!=bgColor) index |= 16;
if (p8!=bgColor) index |= 32;
if (p7!=bgColor) index |= 64;
if (p4!=bgColor) index |= 128;
code = table[index];
if ((pass&1)==1) { //odd pass
if (code==2||code==3) {
v = bgColor;
pixelsRemoved++;
}
} else { //even pass
if (code==1||code==3) {
v = bgColor;
pixelsRemoved++;
}
}
}
pixels[offset++] = (byte)v;
}
}
return pixelsRemoved;
}
public void outline() {
process(OUTLINE, 0);
}
}